15(2b-5)+10=10b-16+20b-49

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Solution for 15(2b-5)+10=10b-16+20b-49 equation: 


Simplifying
15(2b + -5) + 10 = 10b + -16 + 20b + -49

Reorder the terms:
15(-5 + 2b) + 10 = 10b + -16 + 20b + -49
(-5 * 15 + 2b * 15) + 10 = 10b + -16 + 20b + -49
(-75 + 30b) + 10 = 10b + -16 + 20b + -49

Reorder the terms:
-75 + 10 + 30b = 10b + -16 + 20b + -49

Combine like terms: -75 + 10 = -65
-65 + 30b = 10b + -16 + 20b + -49

Reorder the terms:
-65 + 30b = -16 + -49 + 10b + 20b

Combine like terms: -16 + -49 = -65
-65 + 30b = -65 + 10b + 20b

Combine like terms: 10b + 20b = 30b
-65 + 30b = -65 + 30b

Add '65' to each side of the equation.
-65 + 65 + 30b = -65 + 65 + 30b

Combine like terms: -65 + 65 = 0
0 + 30b = -65 + 65 + 30b
30b = -65 + 65 + 30b

Combine like terms: -65 + 65 = 0
30b = 0 + 30b
30b = 30b

Add '-30b' to each side of the equation.
30b + -30b = 30b + -30b

Combine like terms: 30b + -30b = 0
0 = 30b + -30b

Combine like terms: 30b + -30b = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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