15(2x+1)=10(3x-2)+35

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Solution for 15(2x+1)=10(3x-2)+35 equation: 


Simplifying
15(2x + 1) = 10(3x + -2) + 35

Reorder the terms:
15(1 + 2x) = 10(3x + -2) + 35
(1 * 15 + 2x * 15) = 10(3x + -2) + 35
(15 + 30x) = 10(3x + -2) + 35

Reorder the terms:
15 + 30x = 10(-2 + 3x) + 35
15 + 30x = (-2 * 10 + 3x * 10) + 35
15 + 30x = (-20 + 30x) + 35

Reorder the terms:
15 + 30x = -20 + 35 + 30x

Combine like terms: -20 + 35 = 15
15 + 30x = 15 + 30x

Add '-15' to each side of the equation.
15 + -15 + 30x = 15 + -15 + 30x

Combine like terms: 15 + -15 = 0
0 + 30x = 15 + -15 + 30x
30x = 15 + -15 + 30x

Combine like terms: 15 + -15 = 0
30x = 0 + 30x
30x = 30x

Add '-30x' to each side of the equation.
30x + -30x = 30x + -30x

Combine like terms: 30x + -30x = 0
0 = 30x + -30x

Combine like terms: 30x + -30x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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