15(2x+1)=3(x+4)-5

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Solution for 15(2x+1)=3(x+4)-5 equation: 



15(2x+1)=3(x+4)-5

We move all terms to the left:

15(2x+1)-(3(x+4)-5)=0

We multiply parentheses

30x-(3(x+4)-5)+15=0



We calculate terms in parentheses: -(3(x+4)-5), so:

3(x+4)-5

We multiply parentheses

3x+12-5

We add all the numbers together, and all the variables

3x+7

Back to the equation:

-(3x+7)



We get rid of parentheses

30x-3x-7+15=0

We add all the numbers together, and all the variables

27x+8=0

We move all terms containing x to the left, all other terms to the right

27x=-8

x=-8/27

x=-8/27

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