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15(2x+3)=9(x+12)
We move all terms to the left:
15(2x+3)-(9(x+12))=0
We multiply parentheses
30x-(9(x+12))+45=0
We calculate terms in parentheses: -(9(x+12)), so:We get rid of parentheses
9(x+12)
We multiply parentheses
9x+108
Back to the equation:
-(9x+108)
30x-9x-108+45=0
We add all the numbers together, and all the variables
21x-63=0
We move all terms containing x to the left, all other terms to the right
21x=63
x=63/21
x=3
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