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15(3+4/5x)=9
We move all terms to the left:
15(3+4/5x)-(9)=0
Domain of the equation: 5x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
15(4/5x+3)-9=0
We multiply parentheses
60x+45-9=0
We add all the numbers together, and all the variables
60x+36=0
We move all terms containing x to the left, all other terms to the right
60x=-36
x=-36/60
x=-3/5
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