15(3b+5)=28

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Solution for 15(3b+5)=28 equation: 



15(3b+5)=28

We move all terms to the left:

15(3b+5)-(28)=0

We multiply parentheses

45b+75-28=0

We add all the numbers together, and all the variables

45b+47=0

We move all terms containing b to the left, all other terms to the right

45b=-47

b=-47/45

b=-1+2/45

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