15(3c-5)=7c-3

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Solution for 15(3c-5)=7c-3 equation: 



15(3c-5)=7c-3

We move all terms to the left:

15(3c-5)-(7c-3)=0

We multiply parentheses

45c-(7c-3)-75=0

We get rid of parentheses

45c-7c+3-75=0

We add all the numbers together, and all the variables

38c-72=0

We move all terms containing c to the left, all other terms to the right

38c=72

c=72/38

c=1+17/19

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