15(3x+12)=-23(x-4)

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Solution for 15(3x+12)=-23(x-4) equation: 



15(3x+12)=-23(x-4)

We move all terms to the left:

15(3x+12)-(-23(x-4))=0

We multiply parentheses

45x-(-23(x-4))+180=0



We calculate terms in parentheses: -(-23(x-4)), so:

-23(x-4)

We multiply parentheses

-23x+92

Back to the equation:

-(-23x+92)



We get rid of parentheses

45x+23x-92+180=0

We add all the numbers together, and all the variables

68x+88=0

We move all terms containing x to the left, all other terms to the right

68x=-88

x=-88/68

x=-1+5/17

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