15(3x-2)=3(2x+1)+2x+1

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Solution for 15(3x-2)=3(2x+1)+2x+1 equation: 



15(3x-2)=3(2x+1)+2x+1

We move all terms to the left:

15(3x-2)-(3(2x+1)+2x+1)=0

We multiply parentheses

45x-(3(2x+1)+2x+1)-30=0



We calculate terms in parentheses: -(3(2x+1)+2x+1), so:

3(2x+1)+2x+1

We add all the numbers together, and all the variables

2x+3(2x+1)+1

We multiply parentheses

2x+6x+3+1

We add all the numbers together, and all the variables

8x+4

Back to the equation:

-(8x+4)



We get rid of parentheses

45x-8x-4-30=0

We add all the numbers together, and all the variables

37x-34=0

We move all terms containing x to the left, all other terms to the right

37x=34

x=34/37

x=34/37

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