15(6c-7)=4c-5

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Solution for 15(6c-7)=4c-5 equation: 



15(6c-7)=4c-5

We move all terms to the left:

15(6c-7)-(4c-5)=0

We multiply parentheses

90c-(4c-5)-105=0

We get rid of parentheses

90c-4c+5-105=0

We add all the numbers together, and all the variables

86c-100=0

We move all terms containing c to the left, all other terms to the right

86c=100

c=100/86

c=1+7/43

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