15(8c-6)=9c-3

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Solution for 15(8c-6)=9c-3 equation: 



15(8c-6)=9c-3

We move all terms to the left:

15(8c-6)-(9c-3)=0

We multiply parentheses

120c-(9c-3)-90=0

We get rid of parentheses

120c-9c+3-90=0

We add all the numbers together, and all the variables

111c-87=0

We move all terms containing c to the left, all other terms to the right

111c=87

c=87/111

c=29/37

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