15(c+4)+c=2(c-5)

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Solution for 15(c+4)+c=2(c-5) equation:


Simplifying
15(c + 4) + c = 2(c + -5)

Reorder the terms:
15(4 + c) + c = 2(c + -5)
(4 * 15 + c * 15) + c = 2(c + -5)
(60 + 15c) + c = 2(c + -5)

Combine like terms: 15c + c = 16c
60 + 16c = 2(c + -5)

Reorder the terms:
60 + 16c = 2(-5 + c)
60 + 16c = (-5 * 2 + c * 2)
60 + 16c = (-10 + 2c)

Solving
60 + 16c = -10 + 2c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-2c' to each side of the equation.
60 + 16c + -2c = -10 + 2c + -2c

Combine like terms: 16c + -2c = 14c
60 + 14c = -10 + 2c + -2c

Combine like terms: 2c + -2c = 0
60 + 14c = -10 + 0
60 + 14c = -10

Add '-60' to each side of the equation.
60 + -60 + 14c = -10 + -60

Combine like terms: 60 + -60 = 0
0 + 14c = -10 + -60
14c = -10 + -60

Combine like terms: -10 + -60 = -70
14c = -70

Divide each side by '14'.
c = -5

Simplifying
c = -5

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