15(c-3)+5=14(5c+4)

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Solution for 15(c-3)+5=14(5c+4) equation: 



15(c-3)+5=14(5c+4)

We move all terms to the left:

15(c-3)+5-(14(5c+4))=0

We multiply parentheses

15c-(14(5c+4))-45+5=0



We calculate terms in parentheses: -(14(5c+4)), so:

14(5c+4)

We multiply parentheses

70c+56

Back to the equation:

-(70c+56)



We add all the numbers together, and all the variables

15c-(70c+56)-40=0

We get rid of parentheses

15c-70c-56-40=0

We add all the numbers together, and all the variables

-55c-96=0

We move all terms containing c to the left, all other terms to the right

-55c=96

c=96/-55

c=-1+41/55

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