15(t-5)+6t=7(3t+5)-11

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Solution for 15(t-5)+6t=7(3t+5)-11 equation: 



15(t-5)+6t=7(3t+5)-11

We move all terms to the left:

15(t-5)+6t-(7(3t+5)-11)=0

We add all the numbers together, and all the variables

6t+15(t-5)-(7(3t+5)-11)=0

We multiply parentheses

6t+15t-(7(3t+5)-11)-75=0



We calculate terms in parentheses: -(7(3t+5)-11), so:

7(3t+5)-11

We multiply parentheses

21t+35-11

We add all the numbers together, and all the variables

21t+24

Back to the equation:

-(21t+24)



We add all the numbers together, and all the variables

21t-(21t+24)-75=0

We get rid of parentheses

21t-21t-24-75=0

We add all the numbers together, and all the variables

-99!=0

There is no solution for this equation

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