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15(x)=60-(x/12)
We move all terms to the left:
15(x)-(60-(x/12))=0
We add all the numbers together, and all the variables
15x-(60-(+x/12))=0
We multiply all the terms by the denominator
15x*12))-(60-(+x=0
We add all the numbers together, and all the variables
x+15x*12))-(60-(=0
Wy multiply elements
180x^2+x=0
a = 180; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·180·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*180}=\frac{-2}{360} =-1/180 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*180}=\frac{0}{360} =0 $
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