15(x+1)+4(x+3)=2(7+x)

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Solution for 15(x+1)+4(x+3)=2(7+x) equation: 



15(x+1)+4(x+3)=2(7+x)

We move all terms to the left:

15(x+1)+4(x+3)-(2(7+x))=0

We add all the numbers together, and all the variables

15(x+1)+4(x+3)-(2(x+7))=0

We multiply parentheses

15x+4x-(2(x+7))+15+12=0



We calculate terms in parentheses: -(2(x+7)), so:

2(x+7)

We multiply parentheses

2x+14

Back to the equation:

-(2x+14)



We add all the numbers together, and all the variables

19x-(2x+14)+27=0

We get rid of parentheses

19x-2x-14+27=0

We add all the numbers together, and all the variables

17x+13=0

We move all terms containing x to the left, all other terms to the right

17x=-13

x=-13/17

x=-13/17

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