15(x+2)-12x=6(x-1)+15

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Solution for 15(x+2)-12x=6(x-1)+15 equation: 



15(x+2)-12x=6(x-1)+15

We move all terms to the left:

15(x+2)-12x-(6(x-1)+15)=0

We add all the numbers together, and all the variables

-12x+15(x+2)-(6(x-1)+15)=0

We multiply parentheses

-12x+15x-(6(x-1)+15)+30=0



We calculate terms in parentheses: -(6(x-1)+15), so:

6(x-1)+15

We multiply parentheses

6x-6+15

We add all the numbers together, and all the variables

6x+9

Back to the equation:

-(6x+9)



We add all the numbers together, and all the variables

3x-(6x+9)+30=0

We get rid of parentheses

3x-6x-9+30=0

We add all the numbers together, and all the variables

-3x+21=0

We move all terms containing x to the left, all other terms to the right

-3x=-21

x=-21/-3

x=+7

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