15(x+2)=7(5x+1)-4

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Solution for 15(x+2)=7(5x+1)-4 equation: 



15(x+2)=7(5x+1)-4

We move all terms to the left:

15(x+2)-(7(5x+1)-4)=0

We multiply parentheses

15x-(7(5x+1)-4)+30=0



We calculate terms in parentheses: -(7(5x+1)-4), so:

7(5x+1)-4

We multiply parentheses

35x+7-4

We add all the numbers together, and all the variables

35x+3

Back to the equation:

-(35x+3)



We get rid of parentheses

15x-35x-3+30=0

We add all the numbers together, and all the variables

-20x+27=0

We move all terms containing x to the left, all other terms to the right

-20x=-27

x=-27/-20

x=1+7/20

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