15(x-2)-21=3(x+1)+6

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Solution for 15(x-2)-21=3(x+1)+6 equation: 



15(x-2)-21=3(x+1)+6

We move all terms to the left:

15(x-2)-21-(3(x+1)+6)=0

We multiply parentheses

15x-(3(x+1)+6)-30-21=0



We calculate terms in parentheses: -(3(x+1)+6), so:

3(x+1)+6

We multiply parentheses

3x+3+6

We add all the numbers together, and all the variables

3x+9

Back to the equation:

-(3x+9)



We add all the numbers together, and all the variables

15x-(3x+9)-51=0

We get rid of parentheses

15x-3x-9-51=0

We add all the numbers together, and all the variables

12x-60=0

We move all terms containing x to the left, all other terms to the right

12x=60

x=60/12

x=5

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