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15(x-3)=10(x+2)-25
We move all terms to the left:
15(x-3)-(10(x+2)-25)=0
We multiply parentheses
15x-(10(x+2)-25)-45=0
We calculate terms in parentheses: -(10(x+2)-25), so:We get rid of parentheses
10(x+2)-25
We multiply parentheses
10x+20-25
We add all the numbers together, and all the variables
10x-5
Back to the equation:
-(10x-5)
15x-10x+5-45=0
We add all the numbers together, and all the variables
5x-40=0
We move all terms containing x to the left, all other terms to the right
5x=40
x=40/5
x=8
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