15(x-4)+18=3x+6(x+4)

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Solution for 15(x-4)+18=3x+6(x+4) equation: 



15(x-4)+18=3x+6(x+4)

We move all terms to the left:

15(x-4)+18-(3x+6(x+4))=0

We multiply parentheses

15x-(3x+6(x+4))-60+18=0



We calculate terms in parentheses: -(3x+6(x+4)), so:

3x+6(x+4)

We multiply parentheses

3x+6x+24

We add all the numbers together, and all the variables

9x+24

Back to the equation:

-(9x+24)



We add all the numbers together, and all the variables

15x-(9x+24)-42=0

We get rid of parentheses

15x-9x-24-42=0

We add all the numbers together, and all the variables

6x-66=0

We move all terms containing x to the left, all other terms to the right

6x=66

x=66/6

x=11

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