15(x-4)-9x+33=9(2-x)-5(x-3)

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Solution for 15(x-4)-9x+33=9(2-x)-5(x-3) equation: 



15(x-4)-9x+33=9(2-x)-5(x-3)

We move all terms to the left:

15(x-4)-9x+33-(9(2-x)-5(x-3))=0

We add all the numbers together, and all the variables

15(x-4)-9x-(9(-1x+2)-5(x-3))+33=0

We add all the numbers together, and all the variables

-9x+15(x-4)-(9(-1x+2)-5(x-3))+33=0

We multiply parentheses

-9x+15x-(9(-1x+2)-5(x-3))-60+33=0



We calculate terms in parentheses: -(9(-1x+2)-5(x-3)), so:

9(-1x+2)-5(x-3)

We multiply parentheses

-9x-5x+18+15

We add all the numbers together, and all the variables

-14x+33

Back to the equation:

-(-14x+33)



We add all the numbers together, and all the variables

6x-(-14x+33)-27=0

We get rid of parentheses

6x+14x-33-27=0

We add all the numbers together, and all the variables

20x-60=0

We move all terms containing x to the left, all other terms to the right

20x=60

x=60/20

x=3

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