15(y+2)=6(2y+7)

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Solution for 15(y+2)=6(2y+7) equation: 



15(y+2)=6(2y+7)

We move all terms to the left:

15(y+2)-(6(2y+7))=0

We multiply parentheses

15y-(6(2y+7))+30=0



We calculate terms in parentheses: -(6(2y+7)), so:

6(2y+7)

We multiply parentheses

12y+42

Back to the equation:

-(12y+42)



We get rid of parentheses

15y-12y-42+30=0

We add all the numbers together, and all the variables

3y-12=0

We move all terms containing y to the left, all other terms to the right

3y=12

y=12/3

y=4

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