15(y-4)=3(2y-15)-(5-2y)

Solution for 15(y-4)=3(2y-15)-(5-2y) equation:

15(y-4)=3(2y-15)-(5-2y)

We move all terms to the left:

15(y-4)-(3(2y-15)-(5-2y))=0

We add all the numbers together, and all the variables

15(y-4)-(3(2y-15)-(-2y+5))=0

We multiply parentheses

15y-(3(2y-15)-(-2y+5))-60=0


We calculate terms in parentheses: -(3(2y-15)-(-2y+5)), so:

3(2y-15)-(-2y+5)

We multiply parentheses

6y-(-2y+5)-45

We get rid of parentheses

6y+2y-5-45

We add all the numbers together, and all the variables

8y-50

Back to the equation:

-(8y-50)


We get rid of parentheses

15y-8y+50-60=0

We add all the numbers together, and all the variables

7y-10=0

We move all terms containing y to the left, all other terms to the right

7y=10

y=10/7

y=1+3/7