15(z+1)-2(z-3)=5(z-2)+7(z-2)

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Solution for 15(z+1)-2(z-3)=5(z-2)+7(z-2) equation: 



15(z+1)-2(z-3)=5(z-2)+7(z-2)

We move all terms to the left:

15(z+1)-2(z-3)-(5(z-2)+7(z-2))=0

We multiply parentheses

15z-2z-(5(z-2)+7(z-2))+15+6=0



We calculate terms in parentheses: -(5(z-2)+7(z-2)), so:

5(z-2)+7(z-2)

We multiply parentheses

5z+7z-10-14

We add all the numbers together, and all the variables

12z-24

Back to the equation:

-(12z-24)



We add all the numbers together, and all the variables

13z-(12z-24)+21=0

We get rid of parentheses

13z-12z+24+21=0

We add all the numbers together, and all the variables

z+45=0

We move all terms containing z to the left, all other terms to the right

z=-45

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