15+(2x-3)=10x-(3x-1)

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Solution for 15+(2x-3)=10x-(3x-1) equation: 



15+(2x-3)=10x-(3x-1)

We move all terms to the left:

15+(2x-3)-(10x-(3x-1))=0

We get rid of parentheses

2x-(10x-(3x-1))-3+15=0



We calculate terms in parentheses: -(10x-(3x-1)), so:

10x-(3x-1)

We get rid of parentheses

10x-3x+1

We add all the numbers together, and all the variables

7x+1

Back to the equation:

-(7x+1)



We add all the numbers together, and all the variables

2x-(7x+1)+12=0

We get rid of parentheses

2x-7x-1+12=0

We add all the numbers together, and all the variables

-5x+11=0

We move all terms containing x to the left, all other terms to the right

-5x=-11

x=-11/-5

x=2+1/5

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