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15+(2x-3)=10x-(3x-6)
We move all terms to the left:
15+(2x-3)-(10x-(3x-6))=0
We get rid of parentheses
2x-(10x-(3x-6))-3+15=0
We calculate terms in parentheses: -(10x-(3x-6)), so:We add all the numbers together, and all the variables
10x-(3x-6)
We get rid of parentheses
10x-3x+6
We add all the numbers together, and all the variables
7x+6
Back to the equation:
-(7x+6)
2x-(7x+6)+12=0
We get rid of parentheses
2x-7x-6+12=0
We add all the numbers together, and all the variables
-5x+6=0
We move all terms containing x to the left, all other terms to the right
-5x=-6
x=-6/-5
x=1+1/5
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