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15+(2x-3)=10x-(4x-1)
We move all terms to the left:
15+(2x-3)-(10x-(4x-1))=0
We get rid of parentheses
2x-(10x-(4x-1))-3+15=0
We calculate terms in parentheses: -(10x-(4x-1)), so:We add all the numbers together, and all the variables
10x-(4x-1)
We get rid of parentheses
10x-4x+1
We add all the numbers together, and all the variables
6x+1
Back to the equation:
-(6x+1)
2x-(6x+1)+12=0
We get rid of parentheses
2x-6x-1+12=0
We add all the numbers together, and all the variables
-4x+11=0
We move all terms containing x to the left, all other terms to the right
-4x=-11
x=-11/-4
x=2+3/4
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