15+(4+k)=15+(k+4)=

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Solution for 15+(4+k)=15+(k+4)= equation: 



15+(4+k)=15+(k+4)=

We move all terms to the left:

15+(4+k)-(15+(k+4))=0

We add all the numbers together, and all the variables

(k+4)-(15+(k+4))+15=0

We get rid of parentheses

k-(15+(k+4))+4+15=0



We calculate terms in parentheses: -(15+(k+4)), so:

15+(k+4)

determiningTheFunctionDomain
(k+4)+15

We get rid of parentheses

k+4+15

We add all the numbers together, and all the variables

k+19

Back to the equation:

-(k+19)



We add all the numbers together, and all the variables

k-(k+19)+19=0

We get rid of parentheses

k-k-19+19=0

We add all the numbers together, and all the variables

=0

k=0/1

k=0

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