15+2n=5+4(n+3)

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Solution for 15+2n=5+4(n+3) equation: 



15+2n=5+4(n+3)

We move all terms to the left:

15+2n-(5+4(n+3))=0



We calculate terms in parentheses: -(5+4(n+3)), so:

5+4(n+3)

determiningTheFunctionDomain
4(n+3)+5

We multiply parentheses

4n+12+5

We add all the numbers together, and all the variables

4n+17

Back to the equation:

-(4n+17)



We get rid of parentheses

2n-4n-17+15=0

We add all the numbers together, and all the variables

-2n-2=0

We move all terms containing n to the left, all other terms to the right

-2n=2

n=2/-2

n=-1

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