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15+2x^2=593
We move all terms to the left:
15+2x^2-(593)=0
We add all the numbers together, and all the variables
2x^2-578=0
a = 2; b = 0; c = -578;
Δ = b2-4ac
Δ = 02-4·2·(-578)
Δ = 4624
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4624}=68$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-68}{2*2}=\frac{-68}{4} =-17 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+68}{2*2}=\frac{68}{4} =17 $
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