15+2z=43-5z

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Solution for 15+2z=43-5z equation: 



15+2z=43-5z

We move all terms to the left:

15+2z-(43-5z)=0

We add all the numbers together, and all the variables

2z-(-5z+43)+15=0

We get rid of parentheses

2z+5z-43+15=0

We add all the numbers together, and all the variables

7z-28=0

We move all terms containing z to the left, all other terms to the right

7z=28

z=28/7

z=4

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