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15+3(x+2)=7x+2(x+1)
We move all terms to the left:
15+3(x+2)-(7x+2(x+1))=0
We multiply parentheses
3x-(7x+2(x+1))+6+15=0
We calculate terms in parentheses: -(7x+2(x+1)), so:We add all the numbers together, and all the variables
7x+2(x+1)
We multiply parentheses
7x+2x+2
We add all the numbers together, and all the variables
9x+2
Back to the equation:
-(9x+2)
3x-(9x+2)+21=0
We get rid of parentheses
3x-9x-2+21=0
We add all the numbers together, and all the variables
-6x+19=0
We move all terms containing x to the left, all other terms to the right
-6x=-19
x=-19/-6
x=3+1/6
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