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15+3r-5=2(r-2)+14
We move all terms to the left:
15+3r-5-(2(r-2)+14)=0
We add all the numbers together, and all the variables
3r-(2(r-2)+14)+10=0
We calculate terms in parentheses: -(2(r-2)+14), so:We get rid of parentheses
2(r-2)+14
We multiply parentheses
2r-4+14
We add all the numbers together, and all the variables
2r+10
Back to the equation:
-(2r+10)
3r-2r-10+10=0
We add all the numbers together, and all the variables
r=0
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