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abs(x^2-x) >= 0;x
x
(2*x+3)/sin(x)
(1/10)^0
5/((x^4+16)^(1/4))
3*(x^2-(2*x)+3)-(2*(x^2-(5*x)-1)) = 0;x
x
| 2(3x-1)=-50 | | 3x-13+6x-7= | | 18-4x+5x=27 | | 4(1-3n)-14=4(2n+3)9n | | 15,6/2,88=x/14 | | -4(-1+3x)=-68 | | 6x-7+3x-13= | | 7f-4-2f=31 | | 2(6-x)-(9x+2)=4+8(x-4) | | 7x-2y-5z=24 | | -1(-3x+5)=22 | | 4x+6+x=-2x+2 | | -4x-2=18+6x | | -9(7+5h)=15 | | n=12+2m | | (4x+1)(2x-2)=8x(x+5) | | -2x-2=3x-22 | | 20=2n+6 | | n=12+2n | | 6x-6=71-x | | 3n=36-6m | | -10=x+2x-7 | | -2(19-8t)=18 | | X/5.1 | | 7x-7+3x=73 | | -5x+8+4x=6 | | x-2-2*ln(x)=0 | | s-10=20.81 | | 6k-10=14 | | 2y+15=23 | | 30m+350=25m+400 | | 6/34=t/108 |