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15-(1/2)x=2
We move all terms to the left:
15-(1/2)x-(2)=0
Domain of the equation: 2)x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
-(+1/2)x+15-2=0
We add all the numbers together, and all the variables
-(+1/2)x+13=0
We multiply parentheses
-x^2+13=0
We add all the numbers together, and all the variables
-1x^2+13=0
a = -1; b = 0; c = +13;
Δ = b2-4ac
Δ = 02-4·(-1)·13
Δ = 52
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{52}=\sqrt{4*13}=\sqrt{4}*\sqrt{13}=2\sqrt{13}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{13}}{2*-1}=\frac{0-2\sqrt{13}}{-2} =-\frac{2\sqrt{13}}{-2} =-\frac{\sqrt{13}}{-1} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{13}}{2*-1}=\frac{0+2\sqrt{13}}{-2} =\frac{2\sqrt{13}}{-2} =\frac{\sqrt{13}}{-1} $
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