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15-(2x+3)=41/5
We move all terms to the left:
15-(2x+3)-(41/5)=0
We add all the numbers together, and all the variables
-(2x+3)+15-(+41/5)=0
We get rid of parentheses
-2x-3+15-41/5=0
We multiply all the terms by the denominator
-2x*5-41-3*5+15*5=0
We add all the numbers together, and all the variables
-2x*5+19=0
Wy multiply elements
-10x+19=0
We move all terms containing x to the left, all other terms to the right
-10x=-19
x=-19/-10
x=1+9/10
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