15-(3x+1)=(x+1)+3x

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Solution for 15-(3x+1)=(x+1)+3x equation: 



15-(3x+1)=(x+1)+3x

We move all terms to the left:

15-(3x+1)-((x+1)+3x)=0

We get rid of parentheses

-3x-((x+1)+3x)-1+15=0



We calculate terms in parentheses: -((x+1)+3x), so:

(x+1)+3x

We add all the numbers together, and all the variables

3x+(x+1)

We get rid of parentheses

3x+x+1

We add all the numbers together, and all the variables

4x+1

Back to the equation:

-(4x+1)



We add all the numbers together, and all the variables

-3x-(4x+1)+14=0

We get rid of parentheses

-3x-4x-1+14=0

We add all the numbers together, and all the variables

-7x+13=0

We move all terms containing x to the left, all other terms to the right

-7x=-13

x=-13/-7

x=1+6/7

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