15-(3x-2)=19-(2x+4)

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Solution for 15-(3x-2)=19-(2x+4) equation: 



15-(3x-2)=19-(2x+4)

We move all terms to the left:

15-(3x-2)-(19-(2x+4))=0

We get rid of parentheses

-3x-(19-(2x+4))+2+15=0



We calculate terms in parentheses: -(19-(2x+4)), so:

19-(2x+4)

determiningTheFunctionDomain
-(2x+4)+19

We get rid of parentheses

-2x-4+19

We add all the numbers together, and all the variables

-2x+15

Back to the equation:

-(-2x+15)



We add all the numbers together, and all the variables

-3x-(-2x+15)+17=0

We get rid of parentheses

-3x+2x-15+17=0

We add all the numbers together, and all the variables

-1x+2=0

We move all terms containing x to the left, all other terms to the right

-x=-2

x=-2/-1

x=+2

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