15-(3x-4)=2*(x-19)-3

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Solution for 15-(3x-4)=2*(x-19)-3 equation:



15-(3x-4)=2(x-19)-3
We move all terms to the left:
15-(3x-4)-(2(x-19)-3)=0
We get rid of parentheses
-3x-(2(x-19)-3)+4+15=0
We calculate terms in parentheses: -(2(x-19)-3), so:
2(x-19)-3
We multiply parentheses
2x-38-3
We add all the numbers together, and all the variables
2x-41
Back to the equation:
-(2x-41)
We add all the numbers together, and all the variables
-3x-(2x-41)+19=0
We get rid of parentheses
-3x-2x+41+19=0
We add all the numbers together, and all the variables
-5x+60=0
We move all terms containing x to the left, all other terms to the right
-5x=-60
x=-60/-5
x=+12

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