15-(4z+.3)=12

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Solution for 15-(4z+.3)=12 equation: 



15-(4z+.3)=12

We move all terms to the left:

15-(4z+.3)-(12)=0

We add all the numbers together, and all the variables

-(4z+0.3)+15-12=0

We add all the numbers together, and all the variables

-(4z+0.3)+3=0

We get rid of parentheses

-4z-0.3+3=0

We add all the numbers together, and all the variables

-4z+2.7=0

We move all terms containing z to the left, all other terms to the right

-4z=-2.7

z=-2.7/-4

z=1/1.48148148148

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