15-(4z+3)=12-z

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Solution for 15-(4z+3)=12-z equation:



15-(4z+3)=12-z
We move all terms to the left:
15-(4z+3)-(12-z)=0
We add all the numbers together, and all the variables
-(4z+3)-(-1z+12)+15=0
We get rid of parentheses
-4z+1z-3-12+15=0
We add all the numbers together, and all the variables
-3z=0
z=0/-3
z=0

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