15-(7+3x)=16-(4x-1)

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Solution for 15-(7+3x)=16-(4x-1) equation: 



15-(7+3x)=16-(4x-1)

We move all terms to the left:

15-(7+3x)-(16-(4x-1))=0

We add all the numbers together, and all the variables

-(3x+7)-(16-(4x-1))+15=0

We get rid of parentheses

-3x-(16-(4x-1))-7+15=0



We calculate terms in parentheses: -(16-(4x-1)), so:

16-(4x-1)

determiningTheFunctionDomain
-(4x-1)+16

We get rid of parentheses

-4x+1+16

We add all the numbers together, and all the variables

-4x+17

Back to the equation:

-(-4x+17)



We add all the numbers together, and all the variables

-3x-(-4x+17)+8=0

We get rid of parentheses

-3x+4x-17+8=0

We add all the numbers together, and all the variables

x-9=0

We move all terms containing x to the left, all other terms to the right

x=9

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