15-(8-5x)=7x+(4-3x)

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Solution for 15-(8-5x)=7x+(4-3x) equation: 



15-(8-5x)=7x+(4-3x)

We move all terms to the left:

15-(8-5x)-(7x+(4-3x))=0

We add all the numbers together, and all the variables

-(-5x+8)-(7x+(-3x+4))+15=0

We get rid of parentheses

5x-(7x+(-3x+4))-8+15=0



We calculate terms in parentheses: -(7x+(-3x+4)), so:

7x+(-3x+4)

We get rid of parentheses

7x-3x+4

We add all the numbers together, and all the variables

4x+4

Back to the equation:

-(4x+4)



We add all the numbers together, and all the variables

5x-(4x+4)+7=0

We get rid of parentheses

5x-4x-4+7=0

We add all the numbers together, and all the variables

x+3=0

We move all terms containing x to the left, all other terms to the right

x=-3

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