15-(x+18)=2(x+1)+3(x-1)

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Solution for 15-(x+18)=2(x+1)+3(x-1) equation: 



15-(x+18)=2(x+1)+3(x-1)

We move all terms to the left:

15-(x+18)-(2(x+1)+3(x-1))=0

We get rid of parentheses

-x-(2(x+1)+3(x-1))-18+15=0



We calculate terms in parentheses: -(2(x+1)+3(x-1)), so:

2(x+1)+3(x-1)

We multiply parentheses

2x+3x+2-3

We add all the numbers together, and all the variables

5x-1

Back to the equation:

-(5x-1)



We add all the numbers together, and all the variables

-1x-(5x-1)-3=0

We get rid of parentheses

-1x-5x+1-3=0

We add all the numbers together, and all the variables

-6x-2=0

We move all terms containing x to the left, all other terms to the right

-6x=2

x=2/-6

x=-1/3

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