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15-(x-9)=3(x+4)-2x
We move all terms to the left:
15-(x-9)-(3(x+4)-2x)=0
We get rid of parentheses
-x-(3(x+4)-2x)+9+15=0
We calculate terms in parentheses: -(3(x+4)-2x), so:We add all the numbers together, and all the variables
3(x+4)-2x
We add all the numbers together, and all the variables
-2x+3(x+4)
We multiply parentheses
-2x+3x+12
We add all the numbers together, and all the variables
x+12
Back to the equation:
-(x+12)
-1x-(x+12)+24=0
We get rid of parentheses
-1x-x-12+24=0
We add all the numbers together, and all the variables
-2x+12=0
We move all terms containing x to the left, all other terms to the right
-2x=-12
x=-12/-2
x=+6
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