15-+5(4c-7)=50

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Solution for 15-+5(4c-7)=50 equation: 



15-+5(4c-7)=50

We move all terms to the left:

15-+5(4c-7)-(50)=0

determiningTheFunctionDomain
5(4c-7)+15-50-=0

We add all the numbers together, and all the variables

5(4c-7)=0

We multiply parentheses

20c-35=0

We move all terms containing c to the left, all other terms to the right

20c=35

c=35/20

c=1+3/4

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