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15-1(x-6)=6-(3x+5)
We move all terms to the left:
15-1(x-6)-(6-(3x+5))=0
We calculate terms in parentheses: -(6-(3x+5)), so:We get rid of parentheses
6-(3x+5)
determiningTheFunctionDomain -(3x+5)+6
We get rid of parentheses
-3x-5+6
We add all the numbers together, and all the variables
-3x+1
Back to the equation:
-(-3x+1)
-1(x-6)+3x-1+15=0
We add all the numbers together, and all the variables
3x-1(x-6)+14=0
We move all terms containing x to the left, all other terms to the right
3x-1(x-6)=-14
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