15-2(3x+5)=6(5+x)

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Solution for 15-2(3x+5)=6(5+x) equation: 



15-2(3x+5)=6(5+x)

We move all terms to the left:

15-2(3x+5)-(6(5+x))=0

We add all the numbers together, and all the variables

-2(3x+5)-(6(x+5))+15=0

We multiply parentheses

-6x-(6(x+5))-10+15=0



We calculate terms in parentheses: -(6(x+5)), so:

6(x+5)

We multiply parentheses

6x+30

Back to the equation:

-(6x+30)



We add all the numbers together, and all the variables

-6x-(6x+30)+5=0

We get rid of parentheses

-6x-6x-30+5=0

We add all the numbers together, and all the variables

-12x-25=0

We move all terms containing x to the left, all other terms to the right

-12x=25

x=25/-12

x=-2+1/12

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