15-3x=x2-2x+1

Solution for 15-3x=x2-2x+1 equation:

15-3x=x2-2x+1

We move all terms to the left:

15-3x-(x2-2x+1)=0

We add all the numbers together, and all the variables

-(+x^2-2x+1)-3x+15=0

We get rid of parentheses

-x^2+2x-3x-1+15=0

We add all the numbers together, and all the variables

-1x^2-1x+14=0

a = -1; b = -1; c = +14;
Δ = b2-4ac
Δ = -12-4·(-1)·14
Δ = 57
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{57}}{2*-1}=\frac{1-\sqrt{57}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{57}}{2*-1}=\frac{1+\sqrt{57}}{-2}
$